Question

An object, 2.0 cm in size, is placed at 20.0 cm in front of a concave
mirror of focal length 15.0 cm. At what distance from the mirror
should a screen be placed in order to obtain a sharp image? Find
the nature and the size of the image

Answer 1

Answer:

$0 = 3214569887()xy { { \frac{ \sqrt{ \sqrt[ | < > \leqslant \geqslant \div \times - + | ]{?} } \times \frac{?}{?} }{?} }^{?} }^{2}$

Answer 2

Answer:

okkkkkkkkkk

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