Question

An object 2 cm high is placed at 1 point a distance of 15 cm from a concave mirror which produces an inverted image 4 cm high. Find the position of the image.

a. 30 cm

b. -30 cm

c. 40 cm

d. -40 cm​

Answer 1

Answer:

∵m=

h

1

h

2

=−

u

v

∴v=

h

1

−h

2

u

Answer 2

Explanation:

Here h

1

= 2 cm, u = -16 cm, h

2

= -3 cm (Since image is real and inverted.)

∵m=

h

1

h

2

=−

u

v

∴v=

h

1

−h

2

u=

2

3

×(−16)=−24cm

f

1

=

v

1

+

u

1

=−

24

1

−

16

1

=

48

−2−3

=

48

−5

;f=

5

−48

=−9.6cm

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