An object 2 cm high is placed at a distance of 16 cm from a concave mirror,which produces 3 cm high inverted image. What is the focal length of the mirror?Also find the position of the image.
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Here h¹ = 2 cm
u = -16cm
h² = -3cm ( Image is real and inverted )
so, m = h²/ h¹ = -v/u
v = - h²/ h¹ × u
v = 3/2 × (-16)
v = -24cm
1/f = 1/v + 1/u
= -1/24 + -1/6
= -2-3/48
= -5/48
1/f = -5/48
f = -48/5
= -9.6cm
The position of the image is in front of the mirror.
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