An object 2 cm high is placed at a distance of 16 cm from a concave mirror
which produces a real image 3 cm high.
(a)What is the focal length of the mirror
(b)Find the position of the image.
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Answer:
Here h
1
= 2 cm, u = -16 cm, h
2
= -3 cm (Since image is real and inverted.)
∵m=
h
1
h
2
=−
u
v
∴v=
h
1
−h
2
u=
2
3
×(−16)=−24cm
f
1
=
v
1
+
u
1
=−
24
1
−
16
1
=
48
−2−3
=
48
−5
;f=
5
−48
=−9.6cm
Explanation:
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