an object 2 cm high is placed at a distance of 16 cm from a concave mirror which produces a reql image 3 cm high .1): what is the focal length of the mirror? .2): find the position of the image
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given,
height of object : 2cm
height of image : 3cm
object distance : 16cm
we know that,
-v/u = hi/ho
-v/-16 = 3/2
-v = -24cm
v = 24cm
from,
1/f = 1/v + 1/u
1/f = (-1/24)+(-1/16)
1/f = -1/4(1/6+1/4)
1/f = -1/4(10/24)
1/f = -5/48
f = -48/5
minus indicate on same side object
height of object : 2cm
height of image : 3cm
object distance : 16cm
we know that,
-v/u = hi/ho
-v/-16 = 3/2
-v = -24cm
v = 24cm
from,
1/f = 1/v + 1/u
1/f = (-1/24)+(-1/16)
1/f = -1/4(1/6+1/4)
1/f = -1/4(10/24)
1/f = -5/48
f = -48/5
minus indicate on same side object
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