Question

an object 2 cm high produce a real image 3 cm high,w hen placed at a distance of 15 cm from concave mirror .calculate the position of image​

Answer 1

Answer:

Since the real image is bigger, it would be farther away from the mirror than the object.

The image and objects form the corresponding sides of similar triangles. Let the image distance be x.

So, 2/3 = 15/x

or x=15 (3/2) = 22.5 cm

Answer 2

here

h1= +2. (since the object is always erect

therefore it will take +ve sign)

h2= -3. (since the image is real therefore

it will be inverted and hence will

take a -ve sign)

now,

u. = -15

so, v = ?

we know,

magnification(mirror) = -v/u. = h2/h11

therefore

-v/-15 = 3/-2

v/15. = 3/-2

v = 15×3/-3

v = 45/-2

v = -22.5cm

PLEASE NOTE THAT (-) SIGN INDICATES FORMATION OF THE IMAGE IN FRONT OF THE MIRROR