Question

an object 2 cm high produces a real image 3 cm when placed at a distance of 15 cm from a concave mirror the position of the image


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Answer 1

here

h1= +2. (since the object is always erect

therefore it will take +ve sign)

h2= -3. (since the image is real therefore

it will be inverted and hence will

take a -ve sign)

now,

u. = -15

so, v = ?

we know,

magnification(mirror) = -v/u. = h2/h11

therefore

-v/-15 = 3/-2

v/15. = 3/-2

v = 15×3/-3

v = 45/-2

v = -22.5cm

PLEASE NOTE THAT (-) SIGN INDICATES FORMATION OF THE IMAGE IN FRONT OF THE MIRROR