an object 2 cm hight is placed at a distance of 16 cm in front of a concave mirror which produces its real image 3 cm
(a)find the position or the image?
(b)what is the focal length of mirror?
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H(o) =2cm
u=-16cm
H(i)=-3cm
-v/u=H(i)/H(o)
-v/(-16)=(-3)/(2)
=>v={(-3)/2}×16
v=-24cm
so, image will be formed 24 cm away from the mirror on the same side as that of object
and , (1/f)=(1/v)+(1/u)
=>(1/f)=(-1/24)+(-1/16)
=> 1/f=(-2)+(-3)/48
=>f=(-48)/5
=>f= -9.6 cm
u=-16cm
H(i)=-3cm
-v/u=H(i)/H(o)
-v/(-16)=(-3)/(2)
=>v={(-3)/2}×16
v=-24cm
so, image will be formed 24 cm away from the mirror on the same side as that of object
and , (1/f)=(1/v)+(1/u)
=>(1/f)=(-1/24)+(-1/16)
=> 1/f=(-2)+(-3)/48
=>f=(-48)/5
=>f= -9.6 cm
chikunonu:
thanks
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