Question

an object 2 cm in size is placed 30 cm in front of a concave mirror of focal length 15cm At what distance from the mirror should screen be placed in order to obtain a sharp image? what will be the nature of the size of the image formed?dreaw a ray diagram to show the formation of the image in this case​

Answer 1

Answer:

GIVEN:-

size of object h = +2cm

distance of object u = -30cm

focal length f = -15cm

by mirror formula, 1/v + 1/u = 1/f

=> 1/v = 1/f - 1/u

=> 1/v = 1/(-15) - 1/(-30)

=> 1/v = 1/30 - 1/15

=> 1/v = (1 - 2)/30

=> 1/v = -1/30

=> v = -30cm

the screen should be placed at 30cm in front of the mirror so, we obtain a real image

magnification, m = h'/h = -v/u

where, h' = size of image

then, h'/h = -v/u

=> h'/2 = -(-30/-30)

=> h' = -2cm

hence, the image formed is real and the same size as object

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Explanation: