Question

An object 2 cm in size is placed 30cm in front of a concave mirror of focal length 15cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? What will be the nature and the size of the image formed? Draw a ray diagram to show the formation of the image in this case.

Answer 1

Concave mirror

Explanation:

Object distance (u) = -30cm

Focal length (f) = -15cm

So, we get image distance v using the mirror formula.

1/u + 1/v = 1/ f

1/v = 1/f - 1/u = 1/-15 - 1/-30 = -1/30

Therefore v = - 30cm

The screen should be placed 30cm in front of the mirror to obtain the real image.

Height of object h1= 2cm;

Magnification =  -vh / u = - [-30(+2) / -30] = -2 cm

So the image formed is at the same position, real, same size, but inverted.

Answer 2

Answer:jgxgvvh

Explanation:

Guhfh