Question

an object 2
cm in size is placed at 30 cm in front of a concave mirror of focal length 15 cm . at what distance from the mirror should a screen be placed in order to obtain a sharp image. find the nature and size of image.​

Answer 1

Answer:

the ans will be 30cm

Explanation:

1/f=1/v+1/u

acc to sign convention u(distance of object)a arend f always negative

-1/15=1/v-1/30

1/v=1/30-1/15

1/v= 1-2/30

1/v=-1/30

v=-30

so distance of image is 30cm behind the mirror

Answer 2

Explanation:

Object distance (u) = -30cm

Focal length (f) = -15cm

So, we get image distance v using the mirror formula.

1/u + 1/v = 1/ f

1/v = 1/f - 1/u = 1/-15 - 1/-30 = -1/30

Therefore v = - 30cm

The screen should be placed 30cm in front of the mirror to obtain the real image.

Height of object h1= 2cm;

Magnification = -vh / u = - [-30(+2) / -30] = -2 cm

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