an object 2 cm tall placed at 40 cm from a convex mirror if it has a focal length of 15 CM then find nature size and position of image
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U(object distance) = -15 as u is always negative
F = -10 (as it is always negative for concave miror and lens )
1/F =1/v + 1/u
-1/10 = 1/v + (-1/15)
-1/10 +1/15 =v
-3+2/30 =v
V=-30cm
Hi/Ho = - V/U
Hi /2 = -(-30/15)
Hi =-30×2÷15
Hi =-4cm (Real and inverted)
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