Question

an object 2 cm tall stands on a principal axis of converging lens of focal length 8 cm find the position nature and size of the image formed if the object is placed 12 cm from the lens, 6 cm from the lens​

Answer 1

Hey mate!

Below is the answer of your question:

Height of object = 2 cm

Focal length = 8 cm

(i) Object distance (u)=12 cm

Using lens formula,

(1/v) - (1/u) = (1/f)

Image distance (v) = + 24 cm

; The image is 24 cm behind the lens ; The nature of the image formed is Real and inverted ;

Height of image = 4 cm

(ii) Object distance (u)= 6 cm

Using lens formula,

(1/v) - (1/u) = (1/f)

Image distance (v) = - 24 cm ; The image is 24 cm in front of the lens ; The nature of the image formed is Virtual and erect ;

Height of image = 8 cm

Hope you understand....

Plz mark as brainliest

Answer 2

Answer:

=2cm

f= +8cm

convex lens

of u= -12 cm

1/v-1/u = 1/f

1/v - 1/-12 = 1/ 8

1/v = 1/8 - 1/12

1/v = 3-2/24

1/v = 1/24

v= 24

m= v/u = h'/h

24/-12=h'/2

24x2/-12 = h'

-4 = h'