Question

An object 20 cm high is placed 50 cm from a concave lens whose focal length is
20 cm.


a. Where is the image located?
b. What is the size of the image?
c. Construct a ray diagram.
d. Describe the image formed.

Answer 1

Explanation:

Focal length f=−20 cm

Focal length f=−20 cmObject distance u=−50 cm

Using 1/v -1 /u = 1/f

Or 1/v - 1/(-50) = 1/-20

We get v=−14.3 cm

Since, v is negative. So image formed is virtual.

Hence, virtual image is formed at a distance of 14.3 cm in front of the lens.

Hope this helps

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