Question

An object 25 cm high is placed in front of a convex lens of focal length 30cm. If the height of the real image formed is 50cm, find the distance between object and image.​

Answer 1

The image is magnified by 0.00024 times. image is real & inverted.

Step-by-step explanation:

We have lens equation :  $(\frac {1}{v}) - (\frac {1}{u}) = \frac {1}{f}$ ..............................(1)

where v is the lens-to-image distance,  

u is lens-to-object distance and f is the focal length

 

By sign convention, u is -ve.

hence from eqn.(1), we get,  $\frac {1}{v} = \frac {1}{30} - \frac {1}{25}$   or v = - 0.006 cm

 

magnification m = $\frac {v}{u} = \frac {-0.006}{(-25)}$ = 0.00024

 

Hence the image is formed on the other side of the lens at a distance 0.006 cm from the lens.

 

The image is magnified by 0.00024 times. image is real and inverted.

Answer 2

Answer:

An object 25 cm high is placed in front of a convex lens of focal length 30cm. If the height of the real image formed is 50cm, find the distance between object and image.

Step-by-step explanation:

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