an object 2cm height is placed at a distance of 16cm from a concave whuch procluces a real image of 3cm high
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We have,
Size of object, h = 2 cm
Object distance, u = -16 cm
Image size, h/ = -3 cm
Image distance, v = ?
Focal length, f = ?
We know,
Magnification, m = -v/u = h//h = -3/2 = -1.5
=> v/u = 1.5
=> v = (u)(1.5) = (-16)(1.5) = -24 cm
Now,
1/f = 1/v + 1/u
=> 1/f = -1/24 – 1/16
=> f = -9.6 cm
Size of object, h = 2 cm
Object distance, u = -16 cm
Image size, h/ = -3 cm
Image distance, v = ?
Focal length, f = ?
We know,
Magnification, m = -v/u = h//h = -3/2 = -1.5
=> v/u = 1.5
=> v = (u)(1.5) = (-16)(1.5) = -24 cm
Now,
1/f = 1/v + 1/u
=> 1/f = -1/24 – 1/16
=> f = -9.6 cm
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