Question

an object 2cm high and forms invested image 3 cm high when the distance between object and image is 10 cm. calculate the nature and focal length of the lens ( pls answer me)​

Answer 1

Answer:

I don't no sorry

Answer 2

Answer:

hope it helps u

Explanation:

Given,

Object height, h

o

=2cm

Object distance, u=32cm

Image height, h

i

=3cm

Magnification, m=

h

o

h

i

=−

u

v

⇒ −

2

3

=

−32

−v

⇒ v=−

2

32×3

v=−48cm= Image distance

From mirror formula,

f

1

=

v

1

+

u

1

f

1

=−

48

1

−

32

1

f=−19.2cm= focal length