Question

An object 2cm high is held 10cm away from a converging lens of focal length 5cm. Find the position , size and nature of the image formed.



CLASS-X
PLS ANSWER FAST
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Answer 1

Answer:

h=2cm

f=5cm

u=10cm

v=?

h'=?

$\frac{1}{f} =\frac{1}{v}-\frac{1}{u} \\so \frac{1}{v} =\frac{1}{f} +\frac{1}{u} \\\frac{1}{v} =\frac{1}{5} +\frac{1}{-10} \\\frac{1}{v}=\frac{1}{10} \\v=10cm\\m=\frac{h}{h'} =\frac{v}{u} \\ \frac{2}{h'}=\frac{10}{-10}\\\\\\by cross multiplication we get \\h'=-2cm$

∴ position of object = 10 cm on other side of the lens on F2

size=h'= 2cm

nature= real and inverted since h' is negative

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