an object 2cm high is located 25 cm in front of a convex mirror of radius of curvature 30cm. find the image position of the image
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f=R/2=30/2=15cm
h=object height=2cm
u=object diatance=25cm
mirror formula ,1/f=1/v+1/u
1/v=1/15-1/25=5-3/75=2/75
v=75/2=37.5 means same sid eof object real image form
m=-v/u=75/2/25=-75/50=-3/2=-1.25
-ve sign shows 1.25 times less size than object
also, m=h'/h
h'=mh=-1.25×2=-2.50cm =height of image
h=object height=2cm
u=object diatance=25cm
mirror formula ,1/f=1/v+1/u
1/v=1/15-1/25=5-3/75=2/75
v=75/2=37.5 means same sid eof object real image form
m=-v/u=75/2/25=-75/50=-3/2=-1.25
-ve sign shows 1.25 times less size than object
also, m=h'/h
h'=mh=-1.25×2=-2.50cm =height of image
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