an object 2cm high is placed at a distance of 10cm from a concave mirror of radius of curvature 40 cm . find the position and size of image formed
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Height of object= 2 cm
u=10 cm(negative)
R=40 cm
f=R/2=20 cm(negative)
1/v+1/u=1/f
1/v=1/f-1/u
1/v=1/-20+1/10
1/v=1/10
v=10 cm(positive)
I/O=-v/u
I=-10/-10×2=2 cm
Thus the image is virtual, formed 10 cm behind the mirror and is erect. It is as the same size of object. Plz Mark ans as brainliest
Sarcastic1:
i guess v will be 20cm
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