Question

An object 2cm high is placed at a distance of 16cm from a concave mirror which produces a real image of 3cm high (a) what is the focal length of the mirror? (b) Find the position of the image. ​

Answer 1

Answer:

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Explanation:

We have,

Size of object, h = 2 cm

Object distance, u = -16 cm

Image size, h/ = -3 cm

Image distance, v = ?

Focal length, f = ?

We know,

Magnification, m = -v/u = h//h = -3/2 = -1.5

=> v/u = 1.5

=> v = (u)(1.5) = (-16)(1.5) = -24 cm

Now,

1/f = 1/v + 1/u

=> 1/f = -1/24 – 1/16

=> f = -9.6 cm