An object 2cm high is placed at distance of 16cm from a concave mirror which produces a real image 3cm high (i) what is the focal length of mirror (ii) find position of image.
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Hey mate ..
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The solution of your given question is :--
Given ,
Object size , h = 2cm
Object distance , u = - 16 cm
Image size , h' = - 3cm ( Since , it is real )
Focal length , f = ?
(ii) We know,
Magnification, m = -v/u = h'/h = -3/2 = -1.5
=> v/u = 1.5
=> v = (u)(1.5) = (-16)(1.5) = -24 cm
Thus , Image distance , v = -24cm
(i) We know,
1/f = 1/v + 1/u ( Since , it is a concave mirror )
=> 1/f = -1/24 – 1/16
=> f = -9.6 cm
Therefore , Required focal length of the mirror , f = -9.6 cm
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LOL .
=========
The solution of your given question is :--
Given ,
Object size , h = 2cm
Object distance , u = - 16 cm
Image size , h' = - 3cm ( Since , it is real )
Focal length , f = ?
(ii) We know,
Magnification, m = -v/u = h'/h = -3/2 = -1.5
=> v/u = 1.5
=> v = (u)(1.5) = (-16)(1.5) = -24 cm
Thus , Image distance , v = -24cm
(i) We know,
1/f = 1/v + 1/u ( Since , it is a concave mirror )
=> 1/f = -1/24 – 1/16
=> f = -9.6 cm
Therefore , Required focal length of the mirror , f = -9.6 cm
========××××××=========
LOL .
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