an object 2cm high is placed in front of converging mirror . if real image is 10 cm tall obtained at 50 cm from the mirror what is the distance of the object from the mirror . also find the focal length of the mirror.
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Answer:
Explanation:
Given that,
Focal length f=
2
R
Radius of curvature R=30
Object distance u=10cm
Height of object h
o
=2cm
From the mirror formula,
f
1
=
v
1
+
u
1
−
v
1
=
u
1
−
f
1
−
v
1
=
10
1
−
30
2
−
v
1
=
30
3−2
v=−30cm
Now, the magnification is
m=
u
−v
m=
10
30
m=3
Now, the height of image
m=
h
o
h
i
3=
2
h
i
h
i
=6cm
Hence, the image distance is −30 cm, height of image is 6 cm and magnification is 3
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