Question

An object 2cm high produce a real image 3cm high, when placed at a distance of 15cm from concave mirror. Calculate the position of the image.

Answer 1

here
h1= +2. (since the object is always erect
therefore it will take +ve sign)
h2= -3. (since the image is real therefore
it will be inverted and hence will
take a -ve sign)
now,
u. = -15
so, v = ?

we know,
magnification(mirror) = -v/u. = h2/h11
therefore
-v/-15 = 3/-2
v/15. = 3/-2
v = 15×3/-3
v = 45/-2
v = -22.5cm
PLEASE NOTE THAT (-) SIGN INDICATES FORMATION OF THE IMAGE IN FRONT OF THE MIRROR

Answer 2

ho (height of object)= +2cm

hi (height of image)= -3cm

u= -15cm

We know that

hi/ho = -v/u

-3/2 = -v/-15

v= -45/2

v= -22.5cm

Hope it helps...