Question

An object 2cm in size is placed 30cm front of a concave mirror of focal length 15cm AT what di3from the mirror should screen be placed in order to obtain a sharp image find the magnification and nature of image also ​

Answer 1

Answer:

34cm

Step-by-step explanation:

pls mark brainliest

Answer 2

Answer:

According to the question:

Object distance, u=−30 cm

Focal length, f=−15 cm

Let the Image distance be v.

By mirror formula:

v1+u1=f1[4pt]

⇒v1+−30 cm1=−15 cm1[4pt]

⇒v1=−−30 cm1+−15 cm1[4pt]

⇒v1=30 cm1−2[4pt]

⇒v1=−30 cm1[4pt]

∴v=−30 cm

Thus, screen should be placed 30 cm in front of the mirror (Centre of curvature) to obtain the real image.

Now,

Height of object, h1=2 cm

Magnification, m=h1h2