an object 2cm tall is placed in front of a concave lens of focal length 20cm . if object distance is 30cm , find image distance ,nature and its height .
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Height of object = 2cm
Object distance = 15cm
Focal length = 10cm
1/f = 1/v +1/u
-1/10 = -1/15 +1/v
1/v = -3 +2 /30
v = -30 cm
Height of image/Height of object = -v /u
Height of image / 2 = 30/-15
Height of image = - 4cm
Nature - Real and inverted
Position - 30 cm from concave mirror
Size = 4 cm
gesurgicals:
It is wrong .....
The question says that object distance is 30 cm .
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