Question

an object 2cm tall is placed on the axis of a convex lens of focal length 5cm at a distance of 10cm from the optical centre of the lens. Find the nature, position and size of the image formed. which case of image formation by convex lenses is illustrated by this example.​

Answer 1

Answer:

Standard thin lens equation will be used

1/f = 1/u + 1/v

F = 5cm

U = 10m = 1000cm

So 1/v = 1/f - 1/u

1/v = 1/5 - 1/1000

Or v = 5.025cm ( the image distance)

The formula for magnification is

M = hi/ho = -v/u

Where hi is the height of the image and ho is the height of the object (=2cm)

Or hi = -vho/u

Or hi = - (5.025x2) / 1000

Or the height of the image is

Hi = 0.01005cm

From the above resutls we can conculde this that

The image is inverted ( hi is negative) Its highly diminished ( hi is smaller than ho) It is the virtual (v is positive)

Answer 2

$Answer$

➡️✨✨ho = 2 cm

f= 5 cm

u= -1000cm

1/f=1/v-1/u

=> 1/5=1/v+1/1000

=>1/v= 1/5-1/1000

1/v=200/100-1/1000

1/v=199/1000

=>v=5.025✨✨

✨✨ hence its solved. ✨✨

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