an object 2cm tall is placed on the axis of a convex lens of focal length 5cm at a distance of 10cm from the optical centre of the lens. Find the nature, position and size of the image formed. which case of image formation by convex lenses is illustrated by this example.
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Answered by
71
Answer:
Standard thin lens equation will be used
1/f = 1/u + 1/v
F = 5cm
U = 10m = 1000cm
So 1/v = 1/f - 1/u
1/v = 1/5 - 1/1000
Or v = 5.025cm ( the image distance)
The formula for magnification is
M = hi/ho = -v/u
Where hi is the height of the image and ho is the height of the object (=2cm)
Or hi = -vho/u
Or hi = - (5.025x2) / 1000
Or the height of the image is
Hi = 0.01005cm
From the above resutls we can conculde this that
The image is inverted ( hi is negative) Its highly diminished ( hi is smaller than ho) It is the virtual (v is positive)
Answered by
2
➡️✨✨ho = 2 cm
f= 5 cm
u= -1000cm
1/f=1/v-1/u
=> 1/5=1/v+1/1000
=>1/v= 1/5-1/1000
1/v=200/100-1/1000
1/v=199/1000
=>v=5.025✨✨
✨✨ hence its solved. ✨✨
✔️✔️
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