Question

an object 3 cm high is placed at adistance of 10 cm infront of aconverging mirror of focal length 20 cm. Find the position, nature and size of the image formed.

Answer 1

Hey, your answer goes like
Focal length of concave mirror = 20 cm
= - 20 cm
Distance of object from mirror (u) = 10 cm
Since u is always negative = -10 cn
Distance of image from mirror (v) = ?

1/f = 1/u + 1/v
1/v = 1/f -1/u
= 1/-20 - 1/-10
=-1-(-2)/20
= -1+2/20
= 1/20
Taking reciprocal,
Therefore , v = 20 cm

As the object is placed at 10 cm which is less than focal length so it is placed between principal focaus and pole of mirror.

So,the image will be formed 20 cm behind the concave mirror , virtual, erect, enlarged and the size will be ---

Height of the object(ho) = 3cm
Height of the image(hi) = ?
hi/ho = -(v/u)
hi/ 3 = -(20/-10)
hi = 3×2
hi = 6 cm

Therefore, size of the image is 6 cm


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