an object 3 cm high is placed at distance of 15 cm from a concave mirror of radius of curvature 20 cm.find the nature,position, size of image
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h=3cm
u=-15cm
f=-10cm
by mirror formula
1/f=1/v+1/u
1/f-1/u=1/v
1/-10-(1/-15)=1/v
1/-10+1/15=1/v
-3+2/30=1/v
-1/30=1/v
there fore v= -30 cm
position of the image is 30 cm from mirror
-ve sign shows that it is in front of the mirror
m=-v/u
m=-(-30)/-15
m=-2
therefore nature of image is 2
h2/h1=m
h2/3=-2
h2=-6cm
there fore height of image is 6 cm
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