Question

An object 3cm high is placed at a distance of 16 cm from a concave mirror which produce a real image 4.5 cm of mirror.what is the focal length of mirror.find the position of the image

Answer 1

Height of the object (h) = 3 cm

Distance of object from concave mirror (u) = -16 cm

Height of the virtual image formed (h') = 4.5 cm

Let's find 'v' first =

- v/u = h'/h

v = - u × h'/h

v = - ( -16) × 4.5 / 3

v = 24 cm

(i) Focal length of mirror = ?

1/f = 1/v + 1/u

1/f = 1/24 + 1/ -16

1/f = -1/48

1 × 48 = -f

f = -48 cm

(ii) Position of image (v) = 24 cm

Answer 2

Answer:

Hey here is your answer

Explanation:

•height of the object (h)= 3 cm

>•Distance of object from concave mirror (u)=

-16cm

● height of the virtual image formed (h') = 4.5 cm

▪let's find 'v' first = -v/u = h'/h

☆ V= -(-16) ×4.5/3

☆V= 24

1) focal length of mirror =?

• 1/f = 1/v + 1/4

• 1|f = 1/24 + 1/-16

• 1|f = -1/48

• 1 × 48 =-f

• f = -48 cm.

2) position of image (v) = 24 cm.