An object 3cm high produces a real image 4.5 cm high when placed at a distance of 20 cm from a conclave mirror ca lcuate the position of image focal length of the conclave mirror
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object height h1=3cm
image height h2=4.5cm
we know
m=h2/h1=-v/u
so,
4.5/3=-v /-20 (object distance =20)
4.5×-20/3=-v
v=30cm
so image is 30 cm from the mirror.
now , using mirror formula
1/u+1/v=1/f
1/-20+1/-30=1/f
-5/60=1/f
-1/12=1/f
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