Question

An object 3cm high produces a real image 9cm high when placed at a distance 20cm from a concave
mirror. Calculate: (1) position of the image ta Focal length of the mirror
State the nature of the lens and the focal length of its power is +255D.​

Answer 1

Answer:

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Explanation:

Given,

size of the object , h = +3 cm

object distance , u = 15 cm

focal length , f = + 10 cm ( f is +ve for a convex lens )

By lens formula ,

1/v - 1/u = 1/f

1/v= 1/u +1/f

= 1/-15 +1/10

-2+3/30

= 1/30

image distance v,= +30 cm

magnification , m = h'/h = v/u

Image size ,

h' = vh/u = (+30) (3) /-15 = -6 cm

As v is +ve and h' is -ve so a real and inverted image is formed at 30 cm behind the lens