An object 4.0 cm in size is placed at 25.0 cm in front of concave mirror of focal length 15.0 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? Find the nature and size of the image
1) v=-37.5 cm, Image is inverted and enlarge
2)v=37.5 cm, Image is erect and diminished
3)v=-12.5 cm, Image is inverted and enlarge
4)v=12.5 cm, Image is erect and diminished
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GIVEN :
- Size of an object is 4.0 cm.
- Object is placed at 25.0 cm in front of a concave mirror.
- Focal length = 15.0 cm.
TO FIND :
- At what distance from the mirror should a screen be placed in order to obtain a sharp image ?
- Nature and size of the image.
FORMULAS USED :
- Distance of the image =
- Size of the image =
SOLUTION :
To find the distance of the image,
The screen should be placed 37.5 cm in front of lens.
Now,
To find the size of the image,
Size of the image =
The image will be inverted.
Because the value of h is negative.
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1) v=-37.5 cm, Image is Inverted and enlarge...
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