an object 4.0 cm in size is placed at a distance of 25. 0 in front of convex mirror of radius of curvature 40 cm. find the position, size and nature of the image
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The mirror formula is
= 1/f = 1/u + 1/v = 1/-15 = 1/-25 + 1/v
=1/v = 1/25 - 1/15
1/v = 3-5/ 75 =-2/ 75
v =(-37.5 cm )
Magnification, m = { H }{ i } / ho = -v/u = hi / 4 = 37.5 / 25
hi = 37.5 / 25 x 4 = -6 cm
...........
The mirror formula is
= 1/f = 1/u + 1/v = 1/-15 = 1/-25 + 1/v
=1/v = 1/25 - 1/15
1/v = 3-5/ 75 =-2/ 75
v =(-37.5 cm )
Magnification, m = { H }{ i } / ho = -v/u = hi / 4 = 37.5 / 25
hi = 37.5 / 25 x 4 = -6 cm
ttttttt2:
15 kasa aaya
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this math not science
ooooooo
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