an object 4 centimetre in size is placed at a distance of 25 cm from a concave mirror of focal length 15 cm find the position nature and height of the image
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Explanation:
u = 25 cm
f = -15 cm
object height = 4 cm
so, v = fu÷(f-u)
v = 9.375 cm
we have, v/u = h i/h o
9.375/25 = h i/4
h i = 1.5 cm
so, v is 9.375 cm from the pole
v is real and inverted ( v is positive )
height of the object is 1.5 cm
image is smaller than the object
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