An object 4 cm height is placed at 15 cm in front of a concave lens of focal length 10 cm. at what distance from the mirror should a screen be placed to obtain a sharp image of the object. Calculate the height of the image.
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Given :-
f = - 10 cm
u = - 15 cm
h₂ = 4 cm
Solution :-
Using the mirror formula,
1/f = 1/v + 1/u
⇒ 1/v + 1/-15 = 1/- 10
⇒ 1/v = 1/- 10 + 1/15
⇒ 1/v = (- 15 + 10)/150
⇒ 1/v = - 5/150
⇒ v = - 30 cm
Thus, to obtain a sharp image of the object the screen should be placed in front of the mirror at a distance of 30 cm from the mirror.
Magnification, m = - v/u = h₁/h₂
⇒ m = - 30/- 15
⇒ m = - 2
⇒ h₁ = - 8 cm
Hence, the image height will be 8 cm.
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