Question

an object 4 cm high is placed at a distance 27 cm in front of a convex lens of focal length 18 cm .Find the position, nature and size of image​

Answer 1

Step by step explanation;

Using the lens formula; -1/u+1/v=1/f

rearranging, 1/v=1/18-1/27=1/54

hence 1/v=1/54.

To get the position of the image, V, find the reciprocal of 1/54.

Hence, v=54cm.

To obtain the size and nature of image,

use magnifcation formula; hi=V/u*h=54/-27*4=-8.0cm.

Therefore, size of image is 8cm.

Nature=virtual image.

Answer 2

Answer:

v=54

height=-8cm

hope u understand

image is virtual and erect