Question

An object 4 cm high is placed at a distance of 15 cm in front of a concave mirror having radius of curvature 10 cm. Where will image form?​

Answer 1

Answer:

f= - 5, u= -15 As per convention both are negative

Now put in the formula

1/f=1/v+1/u

- 1/5= - 1/15 +1/v

1/v=1/15 - 1/5=(1-3)/15= -2/15

v=-15/2= -7.5 cm

Negative sign shows that image is real and in front of the mirror at a distance of 7.5cm