Question

An object 4 cm high is placed at a distance of 6 cm in front of a concave mirror of focal length 12 cm. Find
the position
, nature and size of the image formed.
[C.B.S.E. 2004 (S)​

Answer 1

Explanation:

Given:

after sign conventions:

f=-12cm

u=-6cm

h0=4cm

By mirror formula,

1/f=1/v+1/u

1/v=1/f-1/u

=1/-12 +1/6

=-1/12+1/6

=1/12

v=12cm

since object is placed between P and F , we get virtual and erect

m=-v/u

=-12/-6

=+2

also m=hi/h0

2=hi/4cm

hi=8cm

hence image is magnified , that is 8cm height.

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