Question

An object 4 cm in height, is placed at 15 cm in front of a concave mirror of radius of curvature 20
cm. At what distance from the mirror should a screen be placed to obtain a sharp image of an object .
Calculate the height of an image

Answer 1

Answer:

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Answer 2

Answer:

The formula related to focal length f, object-to-mirror distance u and image-to-mirror distance v is given by

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \\ \frac{1}{v} + \frac{1}{15} = \frac{1}{10}$

solving for v, we get v = 30 cm. magnification = -v/u = -30/15 = -2; image size = -2×4 = -8 cm (negative sign indicates image is inverted)

Explanation:

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