Question

An object 4 cm in size is placed at 50 cm in front of concave mirror of focal length 25cm. Where is the
image formed and what is the size of the image.
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Answer 1

Answer:

Central curvature(C)

V=4

Explanation:

Length of focal is half of curvature

Focal 25 then curvature is 50

Image formed C is same size of object

Answer 2

Answer:

Given :

object height (ho)=4.0cm

object distance (u)=50.0cm

focal length (f)=25.0cm

using mirror formula:-

1/f=1/u+1/v,

1/25=1/50+1/v,

1/v=1/50-1/25,

1/v=1-2/50,

1/v=-1/50,

v=-50.

image distance (v)= -50

and center of curvature= 2×focal length

=2x25.0

=50.0

I.e, the image formed at center of curvature..

using magnified formula,

hi/ho= -v/u

hi= -v/u×ho

hi=-(-50)/50×4

hi=4

: size of image=4.