Question

An object 4 cm in size is placed at 50 cm in front of a concave mirror and its focal length is 15 cm find object distance .At what distance from the mirror should screen form. Find the nature and size of the image.

please give correct answer...​

Answer 1

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Given,

Focal length, f=15cm

Object distance, u=25cm

Object height, h
0
​
=4cm

From mirror formula,

f
1
​
=
v
1
​
+
u
1
​


−15
1
​
=
−25
1
​
+
v
1
​


⇒
v
1
​
=
−15
1
​
+
25
1
​


v=−37.5cm

magnification, m=−
u
v
​
=
h
0
​

h
i
​

​


⇒m=−
−25
(−37.5)
​
=
4
h
i
​

​


h
i
​
=−
25
37.5×4
​


h
i
​
=−6cm

To get a sharp image, v=37.5cm
The image is real, inverted and magnified