An object 4 cm in size is placed at a distance of 25 cm from a concave mirror of focal length 15 cm. Find the position, nature and height of the image.
Answers
Answered by
2
Explanation:
Focal length, f=15cm
Object distance, u=25cm
Object height, h
0
=4cm
From mirror formula,
f
1
=
v
1
+
u
1
−15
1
=
−25
1
+
v
1
⇒
v
1
=
−15
1
+
25
1
v=−37.5cm
magnification, m=−
u
v
=
h
0
h
i
⇒m=−
−25
(−37.5)
=
4
h
i
h
i
=−
25
37.5×4
h
i
=−6cm
To get a sharp image, v=37.5cm
The image is real, inverted and magnified
Answered by
0
Answer:
Explanation:
Given :
Object distance u = 25 cm
Focal length f = 15 cm
We have mirror formula :
1 / f = 1 / v + 1 / u
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