An object 4cm height is placed at a distance of 5cm from a concave mirror which produces a virtual image 48cm height. What is the focal length of the mirror and also find the position of the mirror?
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given
h = 4 cm
u = -5 cm
h' = 48 cm
we know that h'\h = -v\u
48\4 = -v\5
therefore v = -60 cm
according to light formula,
1\v + 1\u = 1\f
1\-60 + 1\5 = 1\f
therefore f = 5.45 cm
The object is placed between the pole of the mirror and its focal length.
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