Question

An object 4cm high is placed at a distance of 15cm in front of a convex mirror having a radius of curvature of 10cm. Then the image formed is at a distance of______.​

Answer 1

Explanation:

Given, u=−10cm,R=15cm,∴f=

2

R

=−

2

15

cm

From mirror formulae,

v

1

+

u

1

=

f

1

⇒

v

1

=

f

1

−

u

1

⇒

v

1

=

10

1

−

15

2

⇒v=−30

Nature of image is real and inverted.