Question

An object 4cm high is placed at a distance of 6 cm in front of a concave mirror of focal length 12 cm. Find the position, nature and size of the image formed.

Answer 1

we know mirror formula
(1/v)+(1/u)=(1/f)

1. (1/v)=(1/f)-(1/u)
    (1/v)=(1/12)-(1/6)
          = -(1/12)
   So, v = -12cm that means the image will form 12cm away and behind the mirror.

2. image will be of imaginary nature as v is negative

3. By using magnification equation
    M=(hi/ho)= -(v/u)
         (hi/4)= -(-12/6)
              hi=8cm
So the height of the image will be 8cm

Answer 2

Explanation:

there is explanation of the question