Question

An object 4cm high is placed at a distance
of 6cm in front of a concave mirror
of focal length 12cm. find the position
nature and size of the image​

Answer 1

ho= 4cm

u= -6 cm

f = -12 cm

mirror formula :-

1/f = 1/u +1/v

1/v = 1/f - 1/u

1/v = 1/-12 + 1/6

= -1+2/12 ( take the lcm of 12 and 6)

= 1/12

v = 12 (the value is in positive so, the image is formed on the other side of the mirror)

m = -v / u

= - 12 / - 6

= 2

(the value image formed is virtual and erect)

I HOPE IT'S HELPFUL......

Answer 2

Answer:

The object is kept between the focus and pole.

So,the image is enlarged, virtual and erect.

u=(-6)cm

f=(-12)

From mirror formula,

(-1/6)+(1/v)=(-1/12)

1/v=(-1/12)+1/6

1/v=1/12

v=12cm.

Image is formed 12cm behind mirror.

Magnification=(-12/-6)=2

Size of image=4(2)=8cm.

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