Question

An object 4cm high placedat a distance 40cm infront of concave

Answer 1

f=-12 cm

u=-6cm

ho=4cm

by mirror formula

1/v+1/u=1/f

1/v=1/f-1/u

1/v=-1/12+1/6

1/v=1/12

v=12 cm

hence the object is behind the mirror i.e. virtual and erect

m=-v/u

m=-12/-6=+2

alo, m=hi/ho

2=hi/4cm

hi=8 cm

hence image is magnified i.e. 8cm high

HOPE it helps you and plsmark as brainlist