Question

An object 4cm in height is placed at a distance of 36cm from a concave mirror. The image
is formed 18cm in front of the mirror. Find the height of the image.

Answer 1

Given:-

• Height of object (h) = 4 cm

• Distance of object (u) = -36 cm

• Distance of Image (v) = -18 cm

To Find:-

• Height of Image (h')

Formula used:-

• ${\boxed{m = \dfrac{h'}{h} = \dfrac{-v}{u}}}$

Solution:-

$\implies\:\dfrac{h'}{h} = \dfrac{-v}{u}$

$\implies\: \dfrac{h'}{4} = \dfrac{-(-18)}{-36}$

$\implies\: \dfrac{h'}{4} = \dfrac{-18}{36}$

$\implies\: \dfrac{h'}{4} = \dfrac{-1}{2}$

$\implies\: h'= \dfrac{-4}{2}$

${\boxed{\implies\:h' = -2}}$

Hence, The Height of the Image is 2 cm below the principal focus.

More about image:-

• Image is Between focus and the centre of curvature.

• Real and Inverted

• Diminished

━━━━━━━━━━━━━━━━━━━━━━━━━

Answer 2

Answer:

can you friendship with me