Question

An object 4cm in size is placed at 25 cm front of a concave mirror of radius 30 cm. At what distance would a screen be placed in order to get a sharp image? Find the nature and size of the image

Answer 1

Answer:

h=4cm

u=-25

f=R/2

F=-15(since it is a concave mirror)

1/f=I/v+1/u

1/-15+1/25=1/v

1/v=10/375

v=37.5cm

FOR Nature

-v/u

-375/10×-25

1.5=m

therefore the image is virtual,erect and enlarged

FOR Size

h'=-v/u×h

h'=1.5×4

h'=6cm

PLZ MARK IT AS THE BRAINLIEST